With the goal being to find any fit that exists, responder should bid the cheaper four-card suit – ie the one he comes to first as he works up the bidding ladder. That way no fit will be missed.
Exercise: What should you respond to a 1 ♣ opener with these?
Hand i) | Hand ii) | Hand iii) |
♠ A K 4 2 ♥ 9 7 3 ♦ Q 9 7 2 ♣ 3 2 |
♠ K Q 3 2 ♥ J 7 6 2 ♦ J 4 ♣ 7 6 2 |
♠ A J 8 6 2 ♥ A J 7 5 3 ♦ 4 2 ♣ 6 |
With Hand (i) respond 1 ♦, the cheaper of fours. I have seen many bid 1 ♠, muttering words about majors over minors, but the point is that no major-suit fit can be missed by responding 1 ♦ as opener will bid 1 ♠ if he has four spades. And that way the opener, the stronger hand, will be declaring spades, an advantage. Erroneously respond 1 ♠, however, and a diamond fit might be missed.
With Hand (ii) respond 1 ♥, again the cheaper of fours. Not 1 NT – which would deny a higher-ranking four-card suit [or club support – therefore 1 ♣ - 1 NT is an impossible bid!].
With Hand (iii) respond 1 ♠. Whether opener or responder, you should bid five-card suits from the top down. Bid the higher-ranking first, planning to bid the lower ranking next (more
economically).
North Deals None Vul |
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West | North | East | South |
1 ♦ | Pass | 1 ♥1 | |
Pass | 2 ♥ | Pass | 3 NT2 |
Pass | 4 ♥3 | Pass | Pass |
Pass |
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4 ♥ by South |
Lead: ♠ K |
On our deal, a nice 4-4 fit 4 ♥, we see West lead ♠ K. You win ♠ A and lead out ♥ AK. It would be plain sailing if the suit had split 3-2 but, no, East discards on the second round.
Leaving West’s ♥ QJ out, you move to diamonds and must hope for a 3-3 split to avoid losing a spade to go with the certain club and two trumps. You cross to ♦ Q and return to ♦ AK, discarding ♠ 4 as both follow (good). You now lead a fourth diamond (a length winner) and throw ♠ 6 as West trumps. West cashes his other trump and tries ♠ Q but you ruff, play ♣ A and another (losing) and dummy scores the last two tricks, trumping the black-suit return and tabling the long diamond. 10 tricks and game made.